Documents

YearFilenameLanguageSource
1982IMO-1982-problems-eng.pdfen
Problem 1

The function f(n)f(n) is defined for all positive integers nn and takes on non-negative integer values. Also, for all m,nm, n

f(m+n)f(m)f(n)=0 or 1f(m + n) - f(m) - f(n) = 0 \text{ or } 1

f(2)=0,f(3)>0, and f(9999)=3333.f(2) = 0, f(3) > 0, \text{ and } f(9999) = 3333.

Determine f(1982)f(1982).

Problem 2

A non-isosceles triangle A1A2A3A_1A_2A_3 is given with sides a1,a2,a3a_1, a_2, a_3 (aia_i is the side opposite AiA_i). For all i=1,2,3,Mii = 1, 2, 3, M_i is the midpoint of side aia_i, and TiT_i is the point where the incircle touches side aia_i. Denote by SiS_i the reflection of TiT_i in the interior bisector of angle AiA_i. Prove that the lines M1S1M_1S_1, M2S2M_2S_2, and M3S3M_3S_3 are concurrent.

Problem 3

Consider the infinite sequences {xn}\{x_n\} of positive real numbers with the following properties:

x0=1, and for all i0,xi+1xi.x_0 = 1, \text{ and for all } i \geq 0, x_{i+1} \leq x_i.

(a) Prove that for every such sequence, there is an n1n \geq 1 such that

x02x1+x12x2++xn12xn3.999.\frac{x_0^2}{x_1} + \frac{x_1^2}{x_2} + \cdots + \frac{x_{n-1}^2}{x_n} \geq 3.999.

(b) Find such a sequence for which

x02x1+x12x2++xn12xn<4.\frac{x_0^2}{x_1} + \frac{x_1^2}{x_2} + \cdots + \frac{x_{n-1}^2}{x_n} < 4.

Problem 4

Prove that if nn is a positive integer such that the equation

x33xy2+y3=nx^3 - 3xy^2 + y^3 = n

has a solution in integers (x,y)(x, y), then it has at least three such solutions.

Show that the equation has no solutions in integers when n=2891n = 2891.

Problem 5

The diagonals ACAC and CECE of the regular hexagon ABCDEFABCDEF are divided by the inner points MM and NN, respectively, so that

AMAC=CNCE=r.\frac{AM}{AC} = \frac{CN}{CE} = r.

Determine rr if BB, MM, and NN are collinear.

Problem 6

Let SS be a square with sides of length 100, and let LL be a path within SS which does not meet itself and which is composed of line segments A0A1,A1A2,,An1AnA_0A_1, A_1A_2, \ldots, A_{n-1}A_n with A0AnA_0 \neq A_n. Suppose that for every point PP of the boundary of SS there is a point of LL at a distance from PP not greater than 1/21/2. Prove that there are two points XX and YY in LL such that the distance between XX and YY is not greater than 1, and the length of that part of LL which lies between XX and YY is not smaller than 198.