Let Ω\Omega be the circumcircle of a triangle ABCABC with CAB=90\angle CAB = 90^{\circ}. The medians through BB and CC meet Ω\Omega again at DD and EE, respectively. The tangent to Ω\Omega at DD intersects the line ACAC at XX and the tangent to Ω\Omega at EE intersects the line ABAB at YY. Prove that the line XYXY is tangent to Ω\Omega.