Riješite jednadžbu 32log14(x+2)2−3=log14(4−x)3−log4(x+6)3.\frac{3}{2} \log_{\frac{1}{4}}(x + 2)^2 - 3 = \log_{\frac{1}{4}}(4 - x)^3 - \log_4(x + 6)^3.23log41(x+2)2−3=log41(4−x)3−log4(x+6)3.