Let Q>0 be the set of positive rational numbers. Let f:Q>0→R be a function satisfying the following three conditions:
(i) for all x,y∈Q>0, we have f(x)f(y)≥f(xy);
(ii) for all x,y∈Q>0, we have f(x+y)≥f(x)+f(y);
(iii) there exists a rational number a>1 such that f(a)=a.
Prove that f(x)=x for all x∈Q>0.