Initially, only the integer 4444 is written on a board. An integer aa on the board can be replaced with four pairwise different integers a1,a2,a3,a4a_1, a_2, a_3, a_4 such that the arithmetic mean 14(a1+a2+a3+a4)\frac{1}{4}(a_1 + a_2 + a_3 + a_4) of the four new integers is equal to the number aa. In a step we simultaneously replace all the integers on the board in the above way. After 3030 steps we end up with n=430n = 4^{30} integers b1,b2,,bnb_1, b_2, \ldots, b_n on the board. Prove that b12+b22++bn2n2011.\frac{b_1^2 + b_2^2 + \ldots + b_n^2}{n} \geq 2011.