Let ABCABC be a triangle with circumcentre OO. The points PP and QQ are interior points of the sides CACA and ABAB, respectively. Let KK, LL and MM be the midpoints of the segments BPBP, CQCQ and PQPQ, respectively, and let Γ\Gamma be the circle passing through KK, LL and MM. Suppose that the line PQPQ is tangent to the circle Γ\Gamma. Prove that OP=OQOP = OQ.