Let pn(k)p_n(k) be the number of permutations of the set {1,…,n}\{1, \ldots, n\}, n≥1n \geq 1, which have exactly kk fixed points. Prove that

∑k=0nk⋅pn(k)=n!.\sum_{k=0}^{n} k \cdot p_n(k) = n!.

(Remark: A permutation ff of a set SS is a one-to-one mapping of SS onto itself. An element ii in SS is called a fixed point of the permutation ff if f(i)=if(i) = i.)