Let AA be one of the two distinct points of intersection of two unequal coplanar circles C1C_1 and C2C_2 with centers O1O_1 and O2O_2, respectively. One of the common tangents to the circles touches C1C_1 at P1P_1 and C2C_2 at P2P_2, while the other touches C1C_1 at Q1Q_1 and C2C_2 at Q2Q_2. Let M1M_1 be the midpoint of P1Q1P_1Q_1, and M2M_2 be the midpoint of P2Q2P_2Q_2. Prove that O1AO2=M1AM2\angle O_1AO_2 = \angle M_1AM_2.