Let a,b,ca, b, c be the lengths of the sides of a triangle, and α,β,γ\alpha, \beta, \gamma, respectively, the angles opposite these sides. Prove that if a+b=tanγ2(atanα+btanβ),a + b = \tan \frac{\gamma}{2} (a \tan \alpha + b \tan \beta), the triangle is isosceles.