Let R+\mathbb{R}^+ be the set of positive real numbers. Let f ⁣:R+→R+f\colon \mathbb{R}^{+}\to \mathbb{R}^{+} be a function such that for all x,y∈R+x,y\in \mathbb{R}^{+} it holds that

yf2025(x)≥xf(y).y f^{2025}(x) \geq x f(y).

Show that there exists a positive integer n0n_0 such that for all positive integers n≥n0n \geq n_0 and for all x∈R+x \in \mathbb{R}^+ it holds that

fn(x)≥x.f^n(x) \geq x.

Remark. Here fnf^n denotes the function ff applied nn times, this means fn(x)=f(f(…f(x)…))⏟n timesf^n(x) = \underbrace{f(f(\ldots f(x)\ldots))}_{n \text{ times}}.