Let R+\mathbb{R}^+ be the set of positive real numbers. Let f ⁣:R+R+f\colon \mathbb{R}^{+}\to \mathbb{R}^{+} be a function such that for all x,yR+x,y\in \mathbb{R}^{+} it holds that

yf2025(x)xf(y).y f^{2025}(x) \geq x f(y).

Show that there exists a positive integer n0n_0 such that for all positive integers nn0n \geq n_0 and for all xR+x \in \mathbb{R}^+ it holds that

fn(x)x.f^n(x) \geq x.

Remark. Here fnf^n denotes the function ff applied nn times, this means fn(x)=f(f(f(x)))n timesf^n(x) = \underbrace{f(f(\ldots f(x)\ldots))}_{n \text{ times}}.