GCD

14 results

International Mathematical Olympiad 1991 Problem 4

Suppose GG is a connected graph with kk edges. Prove that it is possible to label the edges 1,2,,k1, 2, \ldots, k in such a way that at each vertex which belongs to two or more edges, the greatest common divisor of the integers labeling those edges is equal to 1.

[A graph consists of a set of points, called vertices, together with a set of edges joining certain pairs of distinct vertices. Each pair of vertices u,vu, v belongs to at most one edge. The graph GG is connected if for each pair of distinct vertices x,yx, y there is some sequence of vertices x=v0,v1,v2,,vm=yx = v_0, v_1, v_2, \ldots, v_m = y such that each pair vi,vi+1v_i, v_{i+1} (0i<m0 \leq i < m) is joined by an edge of GG.]

International Mathematical Olympiad 2013 Problem 6

Let n3n \geq 3 be an integer, and consider a circle with n+1n + 1 equally spaced points marked on it. Consider all labellings of these points with the numbers 0,1,,n0, 1, \ldots, n such that each label is used exactly once; two such labellings are considered to be the same if one can be obtained from the other by a rotation of the circle. A labelling is called beautiful if, for any four labels a<b<c<da < b < c < d with a+d=b+ca + d = b + c, the chord joining the points labelled aa and dd does not intersect the chord joining the points labelled bb and cc.

Let MM be the number of beautiful labellings, and let NN be the number of ordered pairs (x,y)(x,y) of positive integers such that x+ynx + y \leq n and gcd(x,y)=1\gcd(x,y) = 1. Prove that

M=N+1.M = N + 1.

International Mathematical Olympiad 2017 Problem 6

An ordered pair (x,y)(x, y) of integers is a primitive point if the greatest common divisor of xx and yy is 1. Given a finite set SS of primitive points, prove that there exist a positive integer nn and integers a0,a1,,ana_0, a_1, \ldots, a_n such that, for each (x,y)(x, y) in SS, we have:

a0xn+a1xn1y+a2xn2y2++an1xyn1+anyn=1.a_0 x^n + a_1 x^{n-1} y + a_2 x^{n-2} y^2 + \cdots + a_{n-1} x y^{n-1} + a_n y^n = 1.

International Mathematical Olympiad 2024 Problem 2

Determine all pairs (a,b)(a, b) of positive integers for which there exist positive integers gg and NN such that gcd(an+b,bn+a)=g\gcd(a^n + b, b^n + a) = g holds for all integers nNn \geq N. (Note that gcd(x,y)\gcd(x, y) denotes the greatest common divisor of integers xx and yy.)

Middle European Mathematical Olympiad 2011 Problem T-8

We call a positive integer nn amazing if there exist positive integers a,b,ca,b,c such that the equality n=(b,c)(a,bc)+(c,a)(b,ca)+(a,b)(c,ab)n=(b,c)(a,bc)+(c,a)(b,ca)+(a,b)(c,ab) holds. Prove that there exist 20112011 consecutive positive integers which are amazing.

(By (m,n)(m,n) we denote the greatest common divisor of positive integers mm and nn.)

Middle European Mathematical Olympiad 2022 Problem I-4

Initially, two positive integers aa and bb with aba \neq b are written on a blackboard. At each step, Andrea picks two numbers xx and yy on the blackboard with xyx \neq y and writes the number

gcd(x,y)+lcm(x,y)\gcd(x, y) + \operatorname{lcm}(x, y)

on the blackboard as well. Let nn be a positive integer. Prove that, regardless of the values of aa and bb, Andrea can perform a finite number of steps such that a multiple of nn appears on the blackboard.

Remark. If xx and yy are two positive integers, then gcd(x,y)\gcd(x, y) denotes their greatest common divisor and lcm(x,y)\operatorname{lcm}(x, y) their least common multiple.

Middle European Mathematical Olympiad 2023 Problem T-8

Let AA and BB be positive integers. Consider a sequence of positive integers (xn)n1(x_{n})_{n\geq 1} such that

xn+1=Agcd(xn,xn1)+Bfor every n2.x_{n+1} = A \cdot \gcd(x_{n}, x_{n-1}) + B \quad \text{for every } n \geq 2.

Prove that the sequence attains only finitely many different values.

Remark. We denote by gcd(a,b)\gcd(a, b) the greatest common divisor of positive integers aa and bb.

Grade 10 2020 Problem 2

Odredi sve uređene parove (a,b)(a,b) prirodnih brojeva takve da je V(a,b)D(a,b)=ab5V(a,b) - D(a,b) = \dfrac{ab}{5}.

Grade 10 2023 Problem 5

Žaba Žana nalazi se ishodištu brojevnog pravca, te u svakom koraku skače za jedan ulijevo, za jedan udesno ili ostaje na mjestu. Lina i Dina izabrale su relativno proste brojeve mm i nn, gdje je m>nm > n. Nakon svakih nn koraka Lina zapovijeda: „Lijevo!", a nakon svakih mm koraka Dina zapovijeda: „Desno!" Žana miruje dok ne čuje prvu zapovijed, a nakon toga počinje (ili nastavlja) skakati u smjeru prema zapovijedi. Zaustavlja se u prvom koraku u kojem čuje obje zapovijedi. U ovisnosti o brojevima mm i nn odredi na kojoj se udaljenosti od ishodišta Žana zaustavila.

Grade 12 2002 Problem 3

Neka je f(x)=x2002x2001+1f(x) = x^{2002} - x^{2001} + 1. Dokazati da su za svaki prirodan broj mm brojevi mm, f(m)f(m), f(f(m))f(f(m)), f(f(f(m)))f(f(f(m))), ..., u parovima relativno prosti, tj. da nikoja dva među njima nemaju zajednički djelitelj veći od 11.

Grade 12 2026 Problem 3

Za uređenu trojku prirodnih brojeva (a,b,c)(a, b, c) kažemo da je morska ako su aa, bb i cc međusobno različiti, te je broj acac djeljiv brojevima a+ba + b i b+cb + c. Dokaži da

a) za svaki prirodni broj d>1d > 1 postoji morska trojka (a,b,c)(a, b, c) za koju je M(a,b,c)=dM(a, b, c) = d.

b) ne postoji morska trojka (a,b,c)(a, b, c) za koju je M(a,b,c)=1M(a, b, c) = 1.

Napomena. M(a,b,c)M(a, b, c) označava najveći zajednički djelitelj brojeva aa, bb i cc.

Grade 12 2024 Problem 4

Odredi sve trojke prirodnih brojeva (m,n,k)(m, n, k) za koje vrijedi D(m,20)=n,D(n,15)=kiD(m,k)=5,D(m, 20) = n, \quad D(n, 15) = k \quad \text{i} \quad D(m, k) = 5, gdje je D(a,b)D(a, b) najveći zajednički djelitelj brojeva aa i bb.