Let ABCABC be an acute-angled triangle with AB<ACAB < AC. Let Ω\Omega be the circumcircle of ABCABC. Let SS be the midpoint of the arc CBCB of Ω\Omega containing AA. The perpendicular from AA to BCBC meets BSBS at DD and meets Ω\Omega again at EAE \neq A. The line through DD parallel to BCBC meets line BEBE at LL. Denote the circumcircle of triangle BDLBDL by ω\omega. Let ω\omega meet Ω\Omega again at PBP \neq B. Prove that the line tangent to ω\omega at PP meets line BSBS on the internal angle bisector of BAC\measuredangle BAC.