Grade 11 2014 Problem 2

Unutar šiljastokutnog trokuta $ABC$ nalazi se točka $P$ takva da je

$$\measuredangle APB = \measuredangle CBA + \measuredangle ACB, \quad \measuredangle BPC = \measuredangle ACB + \measuredangle BAC.$$

Dokaži da vrijedi

$$\frac{|AC| \cdot |BP|}{|BC|} = \frac{|BC| \cdot |AP|}{|AB|}.$$