Let ABCABC be an acute-angled triangle with AB<ACAB < AC, and let DD be the foot of its altitude from AA. Points B′B' and C′C' lie on the rays ABAB and ACAC, respectively, so that points B′B', C′C' and DD are collinear and points BB, CC, B′B' and C′C' lie on one circle with center OO. Prove that if MM is the midpoint of BCBC and HH is the orthocenter of ABCABC, then DHMODHMO is a parallelogram.