Let ABCABC be a triangle. The internal bisector of ABC\angle ABC intersects the side ACAC at LL and the circumcircle of triangle ABCABC again at WBW \neq B. Let KK be the perpendicular projection of LL onto AWAW. The circumcircle of triangle BLCBLC intersects line CKCK again at PCP \neq C. Lines BPBP and AWAW meet at point TT. Prove that AW=WTAW = WT.