Let ABCABC be a triangle. The internal bisector of ∠ABC\angle ABC intersects the side ACAC at LL and the circumcircle of triangle ABCABC again at W≠BW \neq B. Let KK be the perpendicular projection of LL onto AWAW. The circumcircle of triangle BLCBLC intersects line CKCK again at P≠CP \neq C. Lines BPBP and AWAW meet at point TT. Prove that AW=WTAW = WT.