Prove that for all positive real numbers aaa, bbb, ccc such that abc=1abc = 1abc=1 the following inequality holds: a2b+c2+b2c+a2+c2a+b2≤a2+b2+c23.\frac{a}{2b + c^2} + \frac{b}{2c + a^2} + \frac{c}{2a + b^2} \leq \frac{a^2 + b^2 + c^2}{3}.2b+c2a+2c+a2b+2a+b2c≤3a2+b2+c2.