Diophantine

119 results

Croatian Mathematical Olympiad 2012 Problem I-4

Za dani prirodni broj kk neka je S(k)S(k) zbroj svih brojeva iz skupa {1,2,,k}\{1,2,\ldots,k\} koji su relativno prosti s kk. Neka je mm prirodni i nn neparni prirodni broj. Dokaži da postoje prirodni brojevi xx i yy, pri čemu mm dijeli xx, takvi da vrijedi 2S(x)=yn2S(x) = y^n.

Croatian Mathematical Olympiad 2014 Problem M-4

Neka su aa, bb, cc različiti prirodni brojevi i neka su rr, ss, tt prirodni brojevi takvi da vrijedi: ab+1=r2,ac+1=s2,bc+1=t2.ab + 1 = r^2, \quad ac + 1 = s^2, \quad bc + 1 = t^2.

Dokaži da ne mogu sva tri razlomka rst\dfrac{rs}{t}, rts\dfrac{rt}{s}, str\dfrac{st}{r} biti prirodni brojevi.

Croatian Mathematical Olympiad 2022 Problem M-4

Odredi sve trojke prirodnih brojeva (p,m,n)(p, m, n) takve da je pp prost, m<nm < n, sa svojstvom da postoje prirodni brojevi aa, bb, cc, dd koji nisu djeljivi s pp takvi da vrijedi

ab+cd=pm,ac+bd=pn.\begin{aligned} ab + cd &= p^m, \\ ac + bd &= p^n. \end{aligned}

Croatian Mathematical Olympiad 2024 Problem I-4

Odredi sve parove prirodnih brojeva (m,n)(m,n) za koje postoje prirodni brojevi aa, bb, cc i dd takvi da je

manb+ncmd\frac{m^a}{n^b} + \frac{n^c}{m^d}

prirodan broj, ali broj manb\dfrac{m^a}{n^b} nije prirodan.

International Mathematical Olympiad 1982 Problem 4

Prove that if nn is a positive integer such that the equation

x33xy2+y3=nx^3 - 3xy^2 + y^3 = n

has a solution in integers (x,y)(x, y), then it has at least three such solutions.

Show that the equation has no solutions in integers when n=2891n = 2891.

International Mathematical Olympiad 2012 Problem 6

Find all positive integers nn for which there exist non-negative integers a1,a2,,ana_1, a_2, \ldots, a_n such that 12a1+12a2++12an=13a1+23a2++n3an=1.\frac{1}{2^{a_1}} + \frac{1}{2^{a_2}} + \cdots + \frac{1}{2^{a_n}} = \frac{1}{3^{a_1}} + \frac{2}{3^{a_2}} + \cdots + \frac{n}{3^{a_n}} = 1.

International Mathematical Olympiad 2015 Problem 2

Determine all triples (a,b,c)(a, b, c) of positive integers such that each of the numbers abc,bca,cabab - c, \quad bc - a, \quad ca - b is a power of 2.

(A power of 2 is an integer of the form 2n2^n, where nn is a non-negative integer.)

International Mathematical Olympiad 2024 Problem 2

Determine all pairs (a,b)(a, b) of positive integers for which there exist positive integers gg and NN such that gcd(an+b,bn+a)=g\gcd(a^n + b, b^n + a) = g holds for all integers nNn \geq N. (Note that gcd(x,y)\gcd(x, y) denotes the greatest common divisor of integers xx and yy.)

Middle European Mathematical Olympiad 2016 Problem T-8

We consider the equation a2+b2+c2+n=abca^2 + b^2 + c^2 + n = abc, where a,b,ca, b, c are positive integers.

Prove:

(a) There are no solutions (a,b,c)(a,b,c) for n=2017n = 2017.

(b) For n=2016n = 2016, aa must be divisible by 33 for every solution (a,b,c)(a, b, c).

(c) The equation has infinitely many solutions (a,b,c)(a, b, c) for n=2016n = 2016.

Middle European Mathematical Olympiad 2020 Problem I-4

Find all positive integers nn for which there exist positive integers x1,x2,,xnx_1, x_2, \ldots, x_n such that

1x12+2x22+4x32++2n1xn2=1.\dfrac{1}{x_1^2} + \dfrac{2}{x_2^2} + \dfrac{4}{x_3^2} + \cdots + \dfrac{2^{n-1}}{x_n^2} = 1.

Grade 9 2002 Problem 3

Nadite sve trojke (x,y,z)(x, y, z) prirodnih brojeva koji zadovoljavaju jednadžbu 2x2y2+2y2z2+2z2x2x4y4z4=576.2x^2 y^2 + 2y^2 z^2 + 2z^2 x^2 - x^4 - y^4 - z^4 = 576. Naputak: Izraz s lijeve strane jednadžbe rastavite na faktore.