Polynomials

65 results

Croatian Mathematical Olympiad 2011 Problem I-4

Nađi (jedan) cijeli broj aa takav da za polinom P(x)=x5+axP(x) = x^5 + ax tvrdnja ako nP(k)P(l) onda nkl, za sve k,lZ\text{ako } n \mid P(k) - P(l) \text{ onda } n \mid k - l, \text{ za sve } k, l \in \mathbb{Z} vrijedi samo za konačno mnogo prirodnih brojeva nn, među kojima je i n=95n = 95.

Croatian Mathematical Olympiad 2018 Problem I-1

Neka su P(x)P(x) i Q(x)Q(x) polinomi s realnim koeficijentima takvi da je

P(P(x))=(Q(x))2P(P(x)) = (Q(x))^2

za svaki realni broj xx. Postoji li nužno polinom R(x)R(x), također s realnim koeficijentima, takav da je P(x)=(R(x))2P(x) = (R(x))^2 za svaki realni broj xx?

International Mathematical Olympiad 1967 Problem 5

Consider the sequence {cn}\{c_n\}, where c1=a1+a2++a8c2=a12+a22++a82cn=a1n+a2n++a8n\begin{aligned} c_1 &= a_1 + a_2 + \cdots + a_8 \\ c_2 &= a_1^2 + a_2^2 + \cdots + a_8^2 \\ &\cdots \\ c_n &= a_1^n + a_2^n + \cdots + a_8^n \\ &\cdots \end{aligned} in which a1,a2,,a8a_1, a_2, \ldots, a_8 are real numbers not all equal to zero. Suppose that an infinite number of terms of the sequence {cn}\{c_n\} are equal to zero. Find all natural numbers nn for which cn=0c_n = 0.

International Mathematical Olympiad 1971 Problem 1

Prove that the following assertion is true for n=3n = 3 and n=5n = 5, and that it is false for every other natural number n>2n > 2: If a1,a2,,ana_1, a_2, \ldots, a_n are arbitrary real numbers, then (a1a2)(a1a3)(a1an)+(a2a1)(a2a3)(a2an)(a_1 - a_2)(a_1 - a_3) \cdots (a_1 - a_n) + (a_2 - a_1)(a_2 - a_3) \cdots (a_2 - a_n) ++(ana1)(ana2)(anan1)0+ \cdots + (a_n - a_1)(a_n - a_2) \cdots (a_n - a_{n-1}) \geq 0

International Mathematical Olympiad 1974 Problem 6

Let PP be a non-constant polynomial with integer coefficients. If n(P)n(P) is the number of distinct integers kk such that (P(k))2=1(P(k))^2 = 1, prove that n(P)deg(P)2n(P) - \deg(P) \leq 2, where deg(P)\deg(P) denotes the degree of the polynomial PP.

International Mathematical Olympiad 1975 Problem 6

Find all polynomials PP in two variables, with the following properties: (i) for a positive integer nn and all real t,x,yt, x, y

P(tx,ty)=tnP(x,y)P(tx, ty) = t^n P(x, y)

(that is, PP is homogeneous of degree nn), (ii) for all real a,b,ca, b, c,

P(b+c,a)+P(c+a,b)+P(a+b,c)=0,P(b + c, a) + P(c + a, b) + P(a + b, c) = 0,

(iii) P(1,0)=1P(1, 0) = 1.

International Mathematical Olympiad 1985 Problem 3

For any polynomial P(x)=a0+a1x++akxkP(x) = a_0 + a_1x + \cdots + a_kx^k with integer coefficients, the number of coefficients which are odd is denoted by w(P)w(P). For i=0,1,i = 0, 1, \ldots, let Qi(x)=(1+x)iQ_i(x) = (1+x)^i. Prove that if i1,i2,,ini_1, i_2, \ldots, i_n are integers such that 0i1<i2<<in0 \leq i_1 < i_2 < \cdots < i_n, then w(Qi1+Qi2++Qin)w(Qi1).w(Q_{i_1} + Q_{i_2} + \cdots + Q_{i_n}) \geq w(Q_{i_1}).

International Mathematical Olympiad 1987 Problem 6

Let nn be an integer greater than or equal to 2. Prove that if k2+k+nk^2 + k + n is prime for all integers kk such that 0kn/30 \leq k \leq \sqrt{n/3}, then k2+k+nk^2 + k + n is prime for all integers kk such that 0kn20 \leq k \leq n - 2.

International Mathematical Olympiad 2006 Problem 5

Let P(x)P(x) be a polynomial of degree n>1n > 1 with integer coefficients and let kk be a positive integer. Consider the polynomial Q(x)=P(P(P(P(x))))Q(x) = P(P(\ldots P(P(x)) \ldots)), where PP occurs kk times. Prove that there are at most nn integers tt such that Q(t)=tQ(t) = t.

International Mathematical Olympiad 2016 Problem 4

A set of positive integers is called fragrant if it contains at least two elements and each of its elements has a prime factor in common with at least one of the other elements. Let P(n)=n2+n+1P(n) = n^2 + n + 1. What is the least possible value of the positive integer bb such that there exists a non-negative integer aa for which the set {P(a+1),P(a+2),,P(a+b)}\{P(a + 1), P(a + 2), \ldots, P(a + b)\} is fragrant?

International Mathematical Olympiad 2016 Problem 5

The equation (x1)(x2)(x2016)=(x1)(x2)(x2016)(x - 1)(x - 2) \cdots (x - 2016) = (x - 1)(x - 2) \cdots (x - 2016) is written on the board, with 2016 linear factors on each side. What is the least possible value of kk for which it is possible to erase exactly kk of these 4032 linear factors so that at least one factor remains on each side and the resulting equation has no real solutions?

International Mathematical Olympiad 2017 Problem 6

An ordered pair (x,y)(x, y) of integers is a primitive point if the greatest common divisor of xx and yy is 1. Given a finite set SS of primitive points, prove that there exist a positive integer nn and integers a0,a1,,ana_0, a_1, \ldots, a_n such that, for each (x,y)(x, y) in SS, we have:

a0xn+a1xn1y+a2xn2y2++an1xyn1+anyn=1.a_0 x^n + a_1 x^{n-1} y + a_2 x^{n-2} y^2 + \cdots + a_{n-1} x y^{n-1} + a_n y^n = 1.

International Mathematical Olympiad 2022 Problem 3

Let kk be a positive integer and let SS be a finite set of odd prime numbers. Prove that there is at most one way (up to rotation and reflection) to place the elements of SS around a circle such that the product of any two neighbours is of the form x2+x+kx^2 + x + k for some positive integer xx.

International Mathematical Olympiad 2023 Problem 3

For each integer k2k \geqslant 2, determine all infinite sequences of positive integers a1,a2,a_1, a_2, \ldots for which there exists a polynomial PP of the form P(x)=xk+ck1xk1++c1x+c0P(x) = x^k + c_{k-1}x^{k-1} + \cdots + c_1x + c_0, where c0,c1,,ck1c_0, c_1, \ldots, c_{k-1} are non-negative integers, such that

P(an)=an+1an+2an+kP(a_n) = a_{n+1}a_{n+2}\cdots a_{n+k}

for every integer n1n \geqslant 1.

Middle European Mathematical Olympiad 2018 Problem T-2

Let P(x)P(x) be a polynomial of degree n2n \geq 2 with rational coefficients such that P(x)P(x) has nn pairwise different real roots forming an arithmetic progression. Prove that among the roots of P(x)P(x) there are two that are also the roots of some polynomial of degree 22 with rational coefficients.

Middle European Mathematical Olympiad 2021 Problem T-2

Given a positive integer nn, we say that a polynomial PP with real coefficients is nn-pretty if the equation P(x)=P(x)P(\lfloor x \rfloor) = \lfloor P(x) \rfloor has exactly nn real solutions. Show that for each positive integer nn

(a) there exists an nn-pretty polynomial;

(b) any nn-pretty polynomial has a degree of at least 2n+13\frac{2n + 1}{3}.

(Remark. For a real number xx, we denote by x\lfloor x \rfloor the largest integer smaller than or equal to xx.)

Middle European Mathematical Olympiad 2025 Problem T-8

Determine whether the following statement is true for every polynomial PP of degree at least 2 with nonnegative integer coefficients:

There exists a positive integer mm such that for infinitely many positive integers nn the number Pn(m)P^n(m) has more than nn distinct positive divisors.

Remark. Here PnP^n denotes PP applied nn times, this means Pn(x)=P(P(P(x)))n timesP^n(x) = \underbrace{P(P(\ldots P(x)\ldots))}_{n \text{ times}}.

Grade 9 2007 Problem 1

Nadite realna rješenja sustava jednadžbi: x+y+z=2x + y + z = 2 (x+y)(y+z)+(y+z)(z+x)+(z+x)(x+y)=1(x + y)(y + z) + (y + z)(z + x) + (z + x)(x + y) = 1 x2(y+z)+y2(z+x)+z2(x+y)=6x^{2}(y + z) + y^{2}(z + x) + z^{2}(x + y) = -6

Grade 9 2024 Problem 1

Koji je broj veći, A=2022(202422024+1)iliB=20243320242+32024?A = 2022 \cdot (2024^2 - 2024 + 1) \quad \text{ili} \quad B = 2024^3 - 3 \cdot 2024^2 + 3 \cdot 2024?

Grade 9 2026 Problem 1

Izračunaj 220273+2025322+20272025405220273202534052220272025.2 \cdot \frac{2027^{3} + 2025^{3}}{2^{2} + 2027 \cdot 2025} - 4052 \cdot \frac{2027^{3} - 2025^{3}}{4052^{2} - 2027 \cdot 2025}.

Grade 9 2024 Problem 4

Ako za realne brojeve a,b,ca, b, c vrijedi (a+b+c)3=a3+b3+c3(a + b + c)^3 = a^3 + b^3 + c^3, dokaži da je (a+b)2ab+(b+c)2bc+(c+a)2ca+4abc(a+b+c)=0.(a + b)^2 ab + (b + c)^2 bc + (c + a)^2 ca + 4abc(a + b + c) = 0.

Grade 10 1994 Problem 2

Neka je f:RRf: \mathbf{R} \to \mathbf{R} kvadratna funkcija f(x)=ax2+bx+cf(x) = ax^2 + bx + c. Označimo sa DD diskriminantu, sa PP umnožak, a sa SS zbroj njezinih nultočaka. Pokažite da postoji samo jedna funkcija ff za koju su a,D,P,Sa, D, P, S četiri uzastopna cijela broja (u rastućem poretku).

Grade 10 1999 Problem 2

U zavisnosti o parametru aa nađite rješenja jednadžbe x42ax2+x+a2a=0.x^4 - 2ax^2 + x + a^2 - a = 0. Za koje realne brojeve aa su sva rješenja realna?

Grade 10 2002 Problem 1

Nadite sva rješenja jednadžbe (x2+3x4)3+(2x25x+3)3=(3x22x1)3.(x^2 + 3x - 4)^3 + (2x^2 - 5x + 3)^3 = (3x^2 - 2x - 1)^3.

Grade 10 2010 Problem 1

Dokaži da svaki kompleksni broj zz za koji postoji točno jedan kompleksni broj aa takav da je z3+(2a)z2+(13a)z+a2a=0z^3 + (2 - a) z^2 + (1 - 3a) z + a^2 - a = 0 zadovoljava jednakost z3=1z^3 = 1.

Grade 10 2018 Problem 2

Branko ispisuje niz kvadratnih polinoma s realnim koeficijentima. U svakom koraku, nakon prethodno napisanog polinoma ax2+bx+cax^2 + bx + c, zapisuje polinom cx2+bx+acx^2 + bx + a ili polinom a(x+d)2+b(x+d)+ca(x + d)^2 + b(x + d) + c za neki realni broj dd.

Ako započne s polinomom x22x1x^2 - 2x - 1, može li Branko opisanim postupkom nakon određenog broja koraka dobiti polinom:

a) 2x212x^2 - 1?

b) 2x2x12x^2 - x - 1?

Grade 10 2022 Problem 1

Koeficijenti aa, bb i cc kvadratne jednadžbe ax2+bx+c=0ax^2 + bx + c = 0 tri su uzastopna prirodna broja (u nekom od šest mogućih poredaka), a njezina su rješenja realni brojevi. Dokaži da je jedno od rješenja broj 1-1.

Grade 10 2024 Problem 5

Mihael je na ploči zapisao kvadratnu funkciju f(x)f(x) s cjelobrojnim koeficijentima. Nakon toga, u svakom je koraku promijenio (povećao ili smanjio) za 1 ili koeficijent uz xx ili konstantni član. U zadnjem koraku je na ploči zapisana kvadratna funkcija g(x)g(x).

Je li sigurno da je u nekom trenutku na ploči bila zapisana kvadratna funkcija s cjelobrojnim nultočkama ako je

a) f(x)=x2+x+2024f(x) = x^2 + x + 2024 i g(x)=x2+2024x+1g(x) = x^2 + 2024x + 1?

b) f(x)=x2+2024x+2024f(x) = x^2 + 2024x + 2024 i g(x)=x22024x+2024g(x) = x^2 - 2024x + 2024?

Grade 10 2024 Problem 3

Za realne brojeve aa i bb jednadžba x2+ax+b=0x^2 + ax + b = 0 ima dva cjelobrojna rješenja (ne nužno različita). Dokaži da jednadžba x2+5ax+(6a2+b)=0x^2 + 5ax + (6a^2 + b) = 0 također ima dva cjelobrojna rješenja.

Grade 10 2016 Problem 2

Neka su kompleksni brojevi aa, bb i cc rješenja jednadžbe x32x+2=0x^3 - 2x + 2 = 0. Odredi a+1a1+b+1b1+c+1c1.\frac{a + 1}{a - 1} + \frac{b + 1}{b - 1} + \frac{c + 1}{c - 1}.

Grade 11 2018 Problem 2

Neka je S={0,95}S = \{0,95\}. U svakom koraku Lucija proširuje skup SS tako da odabire neki polinom s koeficijentima iz SS, različit od nulpolinoma, te skupu SS dodaje sve cjelobrojne nultočke tog polinoma. Postupak nastavlja odabirom drugog polinoma s koeficijentima iz tako proširenog skupa SS dok god na taj način može dobiti nove nultočke.

Dokaži da Lucija može konačnim nizom koraka proširiti skup SS do skupa koji nije moguće dalje proširiti. Koliko elemenata tada ima skup SS?