#CompetitionYearsProblemsYears
1International Mathematical Olympiad1959–2025398
2Middle European Mathematical Olympiad2009–2025160
International Mathematical Olympiad 2020 Problem 1

Consider the convex quadrilateral ABCDABCD. The point PP is in the interior of ABCDABCD. The following ratio equalities hold: PAD:PBA:DPA=1:2:3=CBP:BAP:BPC.\angle PAD : \angle PBA : \angle DPA = 1 : 2 : 3 = \angle CBP : \angle BAP : \angle BPC.

Prove that the following three lines meet in a point: the internal bisectors of angles ADP\angle ADP and PCB\angle PCB and the perpendicular bisector of segment ABAB.

International Mathematical Olympiad 2020 Problem 3

There are 4n4n pebbles of weights 1,2,3,,4n1, 2, 3, \ldots, 4n. Each pebble is coloured in one of nn colours and there are four pebbles of each colour. Show that we can arrange the pebbles into two piles so that the following two conditions are both satisfied:

  • The total weights of both piles are the same.
  • Each pile contains two pebbles of each colour.
International Mathematical Olympiad 2020 Problem 4

There is an integer n>1n > 1. There are n2n^2 stations on a slope of a mountain, all at different altitudes. Each of two cable car companies, AA and BB, operates kk cable cars; each cable car provides a transfer from one of the stations to a higher one (with no intermediate stops). The kk cable cars of AA have kk different starting points and kk different finishing points, and a cable car which starts higher also finishes higher. The same conditions hold for BB. We say that two stations are linked by a company if one can start from the lower station and reach the higher one by using one or more cars of that company (no other movements between stations are allowed).

Determine the smallest positive integer kk for which one can guarantee that there are two stations that are linked by both companies.

International Mathematical Olympiad 2020 Problem 5

A deck of n>1n > 1 cards is given. A positive integer is written on each card. The deck has the property that the arithmetic mean of the numbers on each pair of cards is also the geometric mean of the numbers on some collection of one or more cards.

For which nn does it follow that the numbers on the cards are all equal?

International Mathematical Olympiad 2020 Problem 6

Prove that there exists a positive constant cc such that the following statement is true:

Consider an integer n>1n > 1, and a set SS of nn points in the plane such that the distance between any two different points in SS is at least 1. It follows that there is a line \ell separating SS such that the distance from any point of SS to \ell is at least cn1/3cn^{-1/3}.

(A line \ell separates a set of points SS if some segment joining two points in SS crosses \ell.)

Note. Weaker results with cn1/3cn^{-1/3} replaced by cnαcn^{-\alpha} may be awarded points depending on the value of the constant α>1/3\alpha > 1/3.

Middle European Mathematical Olympiad 2020 Problem I-1

Let N\mathbb{N} be the set of positive integers. Determine all positive integers kk for which there exist functions f ⁣:NNf\colon \mathbb{N}\to \mathbb{N} and g ⁣:NNg\colon \mathbb{N}\to \mathbb{N} such that gg assumes infinitely many values and such that

fg(n)(n)=f(n)+kf^{g(n)}(n) = f(n) + k

holds for every positive integer nn.

(Remark. Here, fif^i denotes the function ff applied ii times, i.e., fi(j)=f(f(f(f(j))))i timesf^i(j) = \underbrace{f(f(\ldots f(f(j)) \ldots))}_{i \text{ times}}.)

Middle European Mathematical Olympiad 2020 Problem I-3

Let ABCABC be an acute scalene triangle with circumcircle ω\omega and incenter II. Suppose the orthocenter HH of BICBIC lies inside ω\omega. Let MM be the midpoint of the longer arc BCBC of ω\omega. Let NN be the midpoint of the shorter arc AMAM of ω\omega.

Prove that there exists a circle tangent to ω\omega at NN and tangent to the circumcircles of BHIBHI and CHICHI.

Middle European Mathematical Olympiad 2020 Problem I-4

Find all positive integers nn for which there exist positive integers x1,x2,,xnx_1, x_2, \ldots, x_n such that

1x12+2x22+4x32++2n1xn2=1.\dfrac{1}{x_1^2} + \dfrac{2}{x_2^2} + \dfrac{4}{x_3^2} + \cdots + \dfrac{2^{n-1}}{x_n^2} = 1.