#CompetitionYearsProblemsYears
1International Mathematical Olympiad1959–2025398
2Middle European Mathematical Olympiad2009–2025160
International Mathematical Olympiad 1973 Problem 1

Point OO lies on line gg; OP1,OP2,,OPn\overrightarrow{OP_1}, \overrightarrow{OP_2}, \ldots, \overrightarrow{OP_n} are unit vectors such that points P1,P2,,PnP_1, P_2, \ldots, P_n all lie in a plane containing gg and on one side of gg. Prove that if nn is odd, OP1+OP2++OPn1\left|\overrightarrow{OP_1} + \overrightarrow{OP_2} + \cdots + \overrightarrow{OP_n}\right| \geq 1

Here OM\left|\overrightarrow{OM}\right| denotes the length of vector OM\overrightarrow{OM}.

International Mathematical Olympiad 1973 Problem 4

A soldier needs to check on the presence of mines in a region having the shape of an equilateral triangle. The radius of action of his detector is equal to half the altitude of the triangle. The soldier leaves from one vertex of the triangle. What path should he follow in order to travel the least possible distance and still accomplish his mission?

International Mathematical Olympiad 1973 Problem 5

GG is a set of non-constant functions of the real variable xx of the form f(x)=ax+b, a and b are real numbers,f(x) = ax + b, \text{ } a \text{ and } b \text{ are real numbers,} and GG has the following properties:

(a) If ff and gg are in GG, then gfg \circ f is in GG; here (gf)(x)=g[f(x)](g \circ f)(x) = g[f(x)].

(b) If ff is in GG, then its inverse f1f^{-1} is in GG; here the inverse of f(x)=ax+bf(x) = ax + b is f1(x)=(xb)/af^{-1}(x) = (x - b)/a.

(c) For every ff in GG, there exists a real number xfx_f such that f(xf)=xff(x_f) = x_f.

Prove that there exists a real number kk such that f(k)=kf(k) = k for all ff in GG.

International Mathematical Olympiad 1973 Problem 6

Let a1,a2,,ana_1, a_2, \ldots, a_n be nn positive numbers, and let qq be a given real number such that 0<q<10 < q < 1. Find nn numbers b1,b2,,bnb_1, b_2, \ldots, b_n for which

(a) ak<bka_k < b_k for k=1,2,,nk = 1, 2, \ldots, n,

(b) q<bk+1bk<1qq < \frac{b_{k+1}}{b_k} < \frac{1}{q} for k=1,2,,n1k = 1, 2, \ldots, n - 1,

(c) b1+b2++bn<1+q1q(a1+a2++an)b_1 + b_2 + \cdots + b_n < \frac{1+q}{1-q}(a_1 + a_2 + \cdots + a_n).